H=t^2+3t+5

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Solution for H=t^2+3t+5 equation: 



=H^2+3H+5

We move all terms to the left:

-(H^2+3H+5)=0

We get rid of parentheses

-H^2-3H-5=0

We add all the numbers together, and all the variables

-1H^2-3H-5=0

a = -1; b = -3; c = -5;
Δ = b2-4ac
Δ = -32-4·(-1)·(-5)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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